1092.03/1000=(1+r)^2

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Solution for 1092.03/1000=(1+r)^2 equation: 


r in (-oo:+oo)

1092.03/1000 = (r+1)^2 // - (r+1)^2

1092.03/1000-(r+1)^2 = 0

1.09203-1*(r+1)^2 = 0

1.09203-1*(r+1)^2 = 0

0.09203-r^2-2*r = 0

0.09203-r^2-2*r = 0

0.09203-r^2-2*r = 0

DELTA = (-2)^2-(-1*0.09203*4)

DELTA = 4.36812

DELTA > 0

r = (4.36812^(1/2)+2)/(-1*2) or r = (2-4.36812^(1/2))/(-1*2)

r = (4.36812^(1/2)+2)/(-2) or r = (2-4.36812^(1/2))/(-2)

(r-((4.36812^(1/2)+2)/(-2)))*(r-((2-4.36812^(1/2))/(-2))) = 0

(r-((4.36812^(1/2)+2)/(-2)))*(r-((2-4.36812^(1/2))/(-2))) = 0

( r-((2-4.36812^(1/2))/(-2)) )

r-((2-4.36812^(1/2))/(-2)) = 0 // + (2-4.36812^(1/2))/(-2)

r = (2-4.36812^(1/2))/(-2)

( r-((4.36812^(1/2)+2)/(-2)) )

r-((4.36812^(1/2)+2)/(-2)) = 0 // + (4.36812^(1/2)+2)/(-2)

r = (4.36812^(1/2)+2)/(-2)

r in { (2-4.36812^(1/2))/(-2), (4.36812^(1/2)+2)/(-2) }

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